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INVCNT - Inversion Count |
Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.
Input
The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.
Output
For every test output one line giving the number of inversions of A.
Example
Input: 2 3 3 1 2 5 2 3 8 6 1 Output: 2 5
Added by: | Paranoid Android |
Date: | 2010-03-06 |
Time limit: | 3.599s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: PERL6 |
hide comments
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2014-11-12 06:59:38 Abi
I dont know ....why iam getting WA :( pls anyone help <snip> Last edit: 2022-06-26 16:05:00 |
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2014-11-08 12:29:10 surayans tiwari(http://bit.ly/1EPzcpv)
acce using merge ,, got acc using fast i/o with bit Last edit: 2014-11-08 12:44:38 |
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2014-10-12 15:39:58 Vikas
I am getting WA even after checking my code many times.Please help. My id is 12607511 |
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2014-09-25 13:49:41 vikax
3 RTE coz of a silly mistake...... finally ac |
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2014-09-23 12:49:05 Siya
AC in first chance :) |
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2014-09-14 14:09:45 saumya
same as http://www.spoj.com/problems/CODESPTB/ just use unsigned long long int.. as said.. it cost me WA !! :/ |
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2014-08-30 13:29:12 Gaurav Ahirwar
0.70 secs AC! :D |
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2014-07-22 10:18:51 ankur manchanda
declare variable count as long long int. It cost me two WA. As in worst case count =2*10^5(2*10^5+1)/2; Last edit: 2014-07-22 10:21:54 |
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2014-07-18 17:30:53 Anmol Pandey
Take array size 10^7+1 to remove SIGSEGV error |
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2014-07-13 09:58:16 dragonemperor
My BIT implementation is giving SIGSEGV. I am not accessing any array out of its bounds. |