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INVCNT - Inversion Count |
Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.
Input
The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.
Output
For every test output one line giving the number of inversions of A.
Example
Input: 2 3 3 1 2 5 2 3 8 6 1 Output: 2 5
Added by: | Paranoid Android |
Date: | 2010-03-06 |
Time limit: | 3.599s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: PERL6 |
hide comments
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2013-04-15 16:21:46 I_AM
Thanks معاذ for your hint. Not taking long long cost me also many wrong answers. Others beware! |
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2013-04-15 16:21:46 Aradhya
did it by merge sort and some hit and trail :D |
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2013-04-15 16:21:46 maaz
Take long long int for the no. of inversions . Cost me many wrong answers. hint: merge sort |
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2013-04-15 16:21:46 N Hari Prasad
try to use printf instead of cout. . got ACC by just changing that. . |
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2013-04-15 16:21:46 Santiago Palacio
@saurabh input and output are separated for the machine (even if they are shown at the same time in the console) |
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2013-04-15 16:21:46 Saurabh Jain
can we print the output of each test case just after we have input the numbers after n and then leave a blank line and read the input for the next text case? |
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2013-04-15 16:21:46 cannot_in2_coding
Last edit: 2011-12-29 23:28:00 |
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2013-04-15 16:21:46 Chandan Giri
@competer thanks :) i was stuck with that |
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2013-04-15 16:21:46 e@spoj
@competer +1 |
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2013-04-15 16:21:46 naive_coder
please have a look at the range that count will have to store :)got AC after i just fixed it Last edit: 2011-08-23 14:15:40 |