INVCNT - Inversion Count

Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6

hide comments
2013-04-15 16:21:46 I_AM
Thanks معاذ for your hint. Not taking long long cost me also many wrong answers. Others beware!
2013-04-15 16:21:46 Aradhya
did it by merge sort and some hit and trail :D
2013-04-15 16:21:46 maaz
Take long long int for the no. of inversions .
Cost me many wrong answers.
hint: merge sort
2013-04-15 16:21:46 N Hari Prasad
try to use printf instead of cout. . got ACC by just changing that. .
2013-04-15 16:21:46 Santiago Palacio
@saurabh input and output are separated for the machine (even if they are shown at the same time in the console)
2013-04-15 16:21:46 Saurabh Jain
can we print the output of each test case just after we have input the numbers after n and then leave a blank line and read the input for the next text case?
2013-04-15 16:21:46 cannot_in2_coding


Last edit: 2011-12-29 23:28:00
2013-04-15 16:21:46 Chandan Giri
@competer thanks :) i was stuck with that
2013-04-15 16:21:46 e@spoj
@competer +1
2013-04-15 16:21:46 naive_coder
please have a look at the range that count will have to store
:)got AC after i just fixed it

Last edit: 2011-08-23 14:15:40
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