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INVCNT - Inversion Count |
Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.
Input
The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.
Output
For every test output one line giving the number of inversions of A.
Example
Input: 2 3 3 1 2 5 2 3 8 6 1 Output: 2 5
Added by: | Paranoid Android |
Date: | 2010-03-06 |
Time limit: | 3.599s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: PERL6 |
hide comments
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2020-05-19 17:39:01
Just solved this question using: 1)merge sort 2)fenwick tree 3)segment tree Now trying with tries:) |
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2020-05-06 05:46:10
Can be Solved Easily with merge sort. Great problem for BIT Practice....Use " Long Long Int ". Hint: use element value. |
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2020-04-21 16:14:30
why tag of Bitmask? how to use Bitmask here?? |
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2020-04-21 07:40:01
I see the question. Okay. Thought of a simple O(n^2) algo. Then I submit and get TLE. Offcourse. Then I see the commenst section. People are commenting about Fenwick trees? Segment trees? Self balancing BST? Now WHAT THE FUCK are these? Spent 2-3 days learning their basics. People who are getting TLE, spend sometime learning these new data structures, ans dont give up. Happy Coding bois edit: The answer can be >2^32, so use long. Things like this should be mentioned in the statment. I wasted 30 mins just because of this Last edit: 2020-04-21 10:15:37 |
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2020-03-29 10:47:02
Solved it With 1)Segment tree 2)fenwick tree (with or without cordinate compression) 3)merge sort 4)policy based data structure in c++ (vary small code, even smaller than fenwick tree) 5)Self Balancing Bst 6) Trie Data Structure (This one is interesting) Last edit: 2020-03-29 10:47:44 |
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2020-03-12 10:57:36
https://youtu.be/B29dVmpIpn0 Check this video if you are not able to understand the merge sort algo |
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2020-02-07 19:18:21
Last edit: 2020-02-08 12:55:30 |
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2020-02-04 08:30:10
1. Do it with merge sort first. 2. Then try it with Fenwick or Binary indexed tree. 3. After that, if you want you can solve it using, * AVL tree (Self-balancing BST) * Segment tree 4. By trying out these things, you will get used to those data structures and algorithms. 5. Also use long data type in java and long long in c++ to count the number of inversions. Last edit: 2020-02-04 08:32:27 |
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2020-01-21 18:22:23
Caution:the answer you are going to print must be of type long long costed me 3 wa's. |
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2020-01-17 03:14:50
AC in one go using merge sort |