INVCNT - Inversion Count

Let A[0 ... n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A.

Input

The first line contains t, the number of testcases followed by a blank space. Each of the t tests start with a number n (n ≤ 200000). Then n + 1 lines follow. In the ith line a number A[i - 1] is given (A[i - 1] ≤ 107). The (n + 1)th line is a blank space.

Output

For every test output one line giving the number of inversions of A.

Example

Input:
2

3
3
1
2

5
2
3
8
6
1


Output:
2
5

Added by:Paranoid Android
Date:2010-03-06
Time limit:3.599s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: PERL6

hide comments
2019-03-27 21:50:29
original problem, I know how to solve it, is O(n ^ 2) okay?
2019-03-27 16:12:41
not bad task...
2019-03-07 13:47:32
SOLVED using BIT in one go
2019-03-06 15:55:46
solved this problem after months. really good question
2019-01-20 19:49:52
@marethyu thank u
2019-01-18 23:37:10
used bit to solve
2019-01-17 09:09:39
Try solving https://codeforces.com/problemset/problem/459/D after you solve this.
2019-01-01 20:58:36
Use long long when counting inversions, it cost me several WAs!
2018-12-23 15:58:33
why others is AC with int althought it has already big number but this one have 2 use long in c++
?? why ??
2018-12-10 23:16:10
Used merge sort..Be careful to use long type instead of integer for count variable. Got wrong answer just for this mistake..
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