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LCA - Lowest Common Ancestor |
A tree is an undirected graph in which any two vertices are connected by exactly one simple path. In other words, any connected graph without cycles is a tree. - Wikipedia
The lowest common ancestor (LCA) is a concept in graph theory and computer science. Let T be a rooted tree with N nodes. The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself). - Wikipedia
Your task in this problem is to find the LCA of any two given nodes v and w in a given tree T.
For example the LCA of nodes 9 and 12 in this tree is the node number 3.
Input
The first line of input will be the number of test cases. Each test case will start with a number N the number of nodes in the tree, 1 ≤ N ≤ 1,000. Nodes are numbered from 1 to N. The next N lines each one will start with a number M the number of child nodes of the Nth node, 0 ≤ M ≤ 999 followed by M numbers the child nodes of the Nth node. The next line will be a number Q the number of queries you have to answer for the given tree T, 1 ≤ Q ≤ 1000. The next Q lines each one will have two number v and w in which you have to find the LCA of v and w in T, 1 ≤ v, w ≤ 1,000.
Input will guarantee that there is only one root and no cycles.
Output
For each test case print Q + 1 lines, The first line will have “Case C:” without quotes where C is the case number starting with 1. The next Q lines should be the LCA of the given v and w respectively.
Example
Input: 1 7 3 2 3 4 0 3 5 6 7 0 0 0 0 2 5 7 2 7 Output: Case 1: 3 1
Added by: | hossamyosef |
Date: | 2013-05-13 |
Time limit: | 0.600s-1.113s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | FCIS/ASU Local Contest 2013 |
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2024-11-22 16:15:25
https://ideone.com/5whup0 Who can help me pls, WA =( [Simes]: I've not tested it, but why did you comment out the writing of the "Case" part? Last edit: 2024-11-22 19:04:17 |
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2024-10-31 22:23:54
Spoj's online judge accepts the naive solution that runs in O(n) time for each query. However, this is a good exercise for practicing fast methods, such as Binary Lifting, Tarjan's offline LCA algorithm, and Euler Tour + RMQ. |
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2024-04-06 05:29:20
Used HLD , getting TLE. logic to find LCA is jumping chains using parent[head] of the chain, until both heads are same. |
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2023-09-13 06:28:48
use sqrt |
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2023-09-13 05:18:07
easy |
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2023-09-13 04:28:07
wow u re so good |
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2023-05-23 09:39:00
AC in one Go , I ued HLD , the best method , search ahegao face on youtube and self pleasure for the rest of the day |
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2023-04-18 16:12:29
It is giving wrong ans, for my accepted code on hackerrank |
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2023-04-08 09:38:10
my code ac in cses and hear give wr and |
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2022-10-09 19:30:55
<snip> [Simes]: Read the footer - Don't post source code here Last edit: 2022-10-09 22:16:31 |