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MULTQ3 - Multiples of 3 |
There are N numbers a[0], a[1] ... a[N - 1]. Initially all are 0. You have to perform two types of operations :
- Increase the numbers between indices A and B (inclusive) by 1. This is represented by the command "0 A B"
- Answer how many numbers between indices A and B (inclusive) are divisible by 3. This is represented by the command "1 A B".
Input
The first line contains two integers, N and Q. Each of the next Q lines are either of the form "0 A B" or "1 A B" as mentioned above.
Output
Output 1 line for each of the queries of the form "1 A B" containing the required answer for the corresponding query.
Sample
Input: 4 7 1 0 3 0 1 2 0 1 3 1 0 0 0 0 3 1 3 3 1 0 3 Output: 4 1 0 2
Constraints
1 ≤ N ≤ 100000
1 ≤ Q ≤ 100000
0 ≤ A ≤ B ≤ N - 1
Added by: | Varun Jalan |
Date: | 2010-09-12 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS OBJC VB.NET |
Resource: | own problem |
hide comments
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2018-10-16 17:50:33
time limit exceeded for java submissions |
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2018-07-24 07:18:11
2D array does the trick :) |
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2018-07-22 19:04:09
use Scanf Printf :-( |
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2018-06-04 15:42:19
Good one....segment trees+lazy propagation!!:) |
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2018-05-05 06:19:25
Can it be solved without using lazy propagation? |
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2018-03-19 12:18:17
Time limit of JAVA is not correct. Same code running in cpp with scanf and printf |
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2018-02-28 19:19:37
AC in 1 go! Nice Problem! :D |
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2018-02-03 13:48:51
Wrote 160 lines of code. AC in ONE GO !!! |
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2018-01-29 20:10:07
Ac in 1 go! can use anything i.e, long long int or int Last edit: 2018-01-29 20:13:06 |
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2018-01-24 17:17:26
Same problem on codechef giving TLE , while AC in one go on SPOJ |