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MULTQ3 - Multiples of 3 |
There are N numbers a[0], a[1] ... a[N - 1]. Initially all are 0. You have to perform two types of operations :
- Increase the numbers between indices A and B (inclusive) by 1. This is represented by the command "0 A B"
- Answer how many numbers between indices A and B (inclusive) are divisible by 3. This is represented by the command "1 A B".
Input
The first line contains two integers, N and Q. Each of the next Q lines are either of the form "0 A B" or "1 A B" as mentioned above.
Output
Output 1 line for each of the queries of the form "1 A B" containing the required answer for the corresponding query.
Sample
Input: 4 7 1 0 3 0 1 2 0 1 3 1 0 0 0 0 3 1 3 3 1 0 3 Output: 4 1 0 2
Constraints
1 ≤ N ≤ 100000
1 ≤ Q ≤ 100000
0 ≤ A ≤ B ≤ N - 1
Added by: | Varun Jalan |
Date: | 2010-09-12 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS OBJC VB.NET |
Resource: | own problem |
hide comments
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2012-10-29 13:28:14 stranger
TLE. i am just tired of problems where io is almost always the only thing that you should care about |
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2012-08-31 10:38:28 Ashok
used getchar_unlocked instead of scanf, still getting tle. |
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2012-08-26 17:54:14 gourav
do we need to use segment tree or something like that |
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2012-08-22 09:24:40 Amit
@Bruno : Thanks ( scanf -> getchar_unlocked() ) |
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2012-07-10 11:31:34 Rohit
gettinngg tle help!! |
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2012-05-09 18:35:12 Rishi Mukherje
Why not increase time limit for languages like python? |
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2011-10-13 20:23:14 Bruno Adami
The time limit is 1 second? o.O, the best solutions are greater than that! Edit-- Its 1 sec per test case.. the time limit is too low, got accepted by changing scanf to getchar_unlocked.. Last edit: 2011-10-18 19:07:19 |
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2011-06-12 12:25:01 oldmonk
getting TLE suggest some method to make it faster |
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2011-02-10 11:00:15 paddyHOD
my answer is correct but it is giving time limit exceeded |
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2010-09-28 07:05:58 Anil Kishore
yes it is, thats why the first query "1 0 3" ( how many of A[0..3] are divisble by 3 ) returns 4 ( all 0s initially ) |