Submit | All submissions | Best solutions | Back to list |
PT07Z - Longest path in a tree |
You are given an unweighted, undirected tree. Write a program to output the length of the longest path (from one node to another) in that tree. The length of a path in this case is number of edges we traverse from source to destination.
Input
The first line of the input file contains one integer N --- number of nodes in the tree (0 < N <= 10000). Next N-1 lines contain N-1 edges of that tree --- Each line contains a pair (u, v) means there is an edge between node u and node v (1 <= u, v <= N).
Output
Print the length of the longest path on one line.
Example
Input: 3 1 2 2 3 Output: 2
Added by: | Thanh-Vy Hua |
Date: | 2007-03-28 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | Co-author Amber |
hide comments
|
||||||||||||||
2015-09-17 17:00:47 :.Mohib.:
Nice...!! |
||||||||||||||
2015-09-16 15:54:02 [Mayank Pratap]
Good prob to increase confidence in tree.. :) |
||||||||||||||
2015-09-08 05:36:36 Guilherme Sena
@Nitesh Tiwari : That is not a tree. (1,2,3,11) is a cycle since edges are undirected. |
||||||||||||||
2015-08-31 12:08:54 Pratik
Very good problem with a simple solution |
||||||||||||||
2015-08-22 14:25:59 ramjeet saran
not a binary tree, cost me 3 WA |
||||||||||||||
2015-08-11 14:35:51 Khanh Ninh
Dynamic Program + DFS , Advanced Solution. |
||||||||||||||
2015-08-04 20:54:44 mohit
DFS! diameter of a tree . http://www.geeksforgeeks.org/diameter-of-a-binary-tree/ |
||||||||||||||
2015-07-30 22:00:44 sameer Hussain
is it a binary tree or any random tree ?? |
||||||||||||||
2015-07-25 23:25:25 Nitesh Tiwari
Answer for the below test case is 6, spojtoolkit is showing 5, I got it accepted with 6. 15 1 2 2 3 1 11 3 11 4 11 4 5 5 6 5 7 6 7 4 12 8 12 9 12 8 10 9 10 |
||||||||||||||
2015-07-22 11:03:16 Krzysztof Strojny
This can be done in in one loop over vertices, take advantage that this is a tree, no need for BFS or DFS |