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PT07Z - Longest path in a tree |
You are given an unweighted, undirected tree. Write a program to output the length of the longest path (from one node to another) in that tree. The length of a path in this case is number of edges we traverse from source to destination.
Input
The first line of the input file contains one integer N --- number of nodes in the tree (0 < N <= 10000). Next N-1 lines contain N-1 edges of that tree --- Each line contains a pair (u, v) means there is an edge between node u and node v (1 <= u, v <= N).
Output
Print the length of the longest path on one line.
Example
Input: 3 1 2 2 3 Output: 2
Added by: | Thanh-Vy Hua |
Date: | 2007-03-28 |
Time limit: | 0.5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | Co-author Amber |
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2019-12-20 16:17:36
the moral of the story is to find the root correctly and calculate the distance from the rooooooooottttttttttt........ |
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2019-11-26 15:30:20
is it a tree problem because there is cycle present like 1 2 2 3, or do i need to learn graph for this |
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2019-11-12 09:40:11
easier then it looks... calc height of each node. then for every node find 2 child with largest height. |
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2019-10-13 02:08:53
https://discuss.codechef.com/t/longest-path-in-a-tree-using-dfs-and-double-bfs/8893 for reference.. |
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2019-09-04 06:04:59
Simple dfs problem ... easy one for beginner... Happy coding |
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2019-08-30 00:30:33
many many thanx @anand_undavia for sharing the link....... https://www.youtube.com/watch?v=w9vjFB7m0PM ...... really helpful :-D Last edit: 2019-08-30 00:32:01 |
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2019-08-24 05:04:07
2 dfs: Start from any node and find the farthest node (say x), now again do a dfs from x and find the farthest node (say y), the answer is distance between x and y. Last edit: 2019-08-24 05:04:21 |
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2019-08-21 15:08:26
Did it using 2-bfs method however was a difficult one as an all new question! |
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2019-08-19 15:58:37
AC in one go!! |
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2019-08-14 22:05:54
using 2 BFS can't do it with DFS acctually idk why xD |