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SUMFOUR - 4 values whose sum is 0 |
The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) belongs to A x B x C x D are such that a + b + c + d = 0. In the following, assume that all lists have the same size n.
Input
The first line of the input file contains the size of the lists n (this value can be as large as 4000). We then have n lines containing four integer values (with absolute value as large as 228 ) that belong respectively to A, B, C and D.
(Edited: n <= 2500)
Output
Output should be printed on a single line.
Example
Input: 6 -45 22 42 -16 -41 -27 56 30 -36 53 -37 77 -36 30 -75 -46 26 -38 -10 62 -32 -54 -6 45 Output: 5
Added by: | Abhilash I |
Date: | 2007-02-06 |
Time limit: | 1.419s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | South western 05-06 |
hide comments
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2018-10-17 22:57:20
unordered_map with reserve keyword got accepted very frustating question takeaway from this question: unordered_map is significantly faster than map and use of 'reserve' can optimize it further Last edit: 2018-10-17 23:09:17 |
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2018-09-29 22:51:02
Lots of optimization required:- - don't use set in cpp - don't use fast_io - don't use long long int - use equal_range instead of upper_bound and lower_bound Last edit: 2018-09-30 12:15:25 |
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2018-09-25 11:04:43
maps sets unordered maps nothing worked! had to write the binary search on my own!! |
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2018-09-04 01:45:45
how cani store integer values (with absolute value as large as 2^28 ) |
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2018-08-21 10:08:44
applied BS but getting WA on 9 again and again! |
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2018-08-17 14:14:48
did you done in java?? if yes, then please help me out.!! |
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2018-07-30 11:36:50
is solution using lower_bound and upper_bounds? |
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2018-06-09 20:25:29
@vengatesh15 Yeah me too!! |
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2018-06-06 19:22:53
Should do with both Hash-Map and Vectors to analysise complexity |
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2018-03-31 13:26:01
@mahabir10 answer to your question should be 8! |