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TRT - Treats for the Cows |
FJ has purchased N (1 <= N <= 2000) yummy treats for the cows who get money for giving vast amounts of milk. FJ sells one treat per day and wants to maximize the money he receives over a given period time. The treats are interesting for many reasons:
- The treats are numbered 1..N and stored sequentially in single file in a long box that is open at both ends. On any day, FJ can retrieve one treat from either end of his stash of treats.
- Like fine wines and delicious cheeses, the treats improve with age and command greater prices.
- The treats are not uniform: some are better and have higher intrinsic value. Treat i has value v(i) (1 <= v(i) <= 1000).
- Cows pay more for treats that have aged longer: a cow will pay v(i)*a for a treat of age a.
Given the values v(i) of each of the treats lined up in order of the index i in their box, what is the greatest value FJ can receive for them if he orders their sale optimally?
The first treat is sold on day 1 and has age a=1. Each subsequent day increases the age by 1.
Input
Line 1: A single integer, N
Lines 2..N+1: Line i+1 contains the value of treat v(i)
Output
The maximum revenue FJ can achieve by selling the treats
Example
Input: 5 1 3 1 5 2 Output: 43
Added by: | Nguyen Van Quang Huy |
Date: | 2006-02-15 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |
Resource: | USACO FEB06 Gold Division |
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2019-01-10 14:46:57
my code runs up to 11 then it shows wrong answer,help me out? |
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2018-10-29 14:34:25
feeling i just got is awesome :)))))) Last edit: 2018-10-29 14:40:54 |
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2018-10-12 10:46:03
There are two things of significance in this problem. First, find a way to represent age in terms of start and end indices so that you don't need it during memoization. Second, something very subtle, using unordered_map gave me TLE, switched to a 2D vector and it passed probably because finding if a key exists is not constant time in all cases whereas if you initialise a 2D vector with dummy values, checking if the key exists is a constant time operation. |
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2018-08-17 11:55:08 Sampath Ravolaparthi
For Newbies out there, I've written a very detailed editorial for this. Check it out https://www.stopstalk.com/problems/read_editorial/31 P.S: The overall complexity is number of pairs (i, j) for 1 to n. ans = n^2 |
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2018-06-27 18:59:16
Think about the recursive approach first. |
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2018-06-27 10:45:55
Last edit: 2018-06-27 15:34:22 |
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2018-06-08 04:59:22
A very very nice problem....variation of matrix chain multiplication but this time i did it totally by myselef. |
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2018-06-05 14:21:19
Nothing is wrong with the test case 12 . Just make sure that you are using the storage array within bounds [2001][2001] . Last edit: 2018-06-06 09:23:51 |
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2018-03-10 10:06:18
Don't even bother trying to do it in Python. I did it in Python using what I'm sure was an optimal algorithm and TLE'ed. Eventually decided to convert my algorithm to C++ despite not having used that language for 10 years. Result was 0.00 second AC. |
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2018-02-03 11:57:42
similar problem TWENDS. |