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ABCDEF - ABCDEF |
You are given a set S of integers between -30000 and 30000 (inclusive).
Find the total number of sextuples that satisfy:
Input
The first line contains integer N (1 ≤ N ≤ 100), the size of a set S.
Elements of S are given in the next N lines, one integer per line. Given numbers will be distinct.
Output
Output the total number of plausible sextuples.
Examples
Input: 1 1 Output: 1 |
Input: 2 2 3 Output: 4 |
Input: 2 -1 1 Output: 24 |
Input: 3 5 7 10 Output: 10 |
Added by: | Luka Kalinovcic |
Date: | 2009-07-13 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | own problem |
hide comments
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2019-09-28 11:25:16
Be careful with d!=0 ;) Last edit: 2019-09-28 11:26:27 |
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2019-08-06 17:09:17
you traverse through each element of the set using three loops to assign all the possible value to LHS and RHS avoiding d=0, use one vector for LHS and another vector for rhs values, sort both the vectors, traverse through LHS and find the occurrence of each element in RHS and add this to result print result, you can find occurrence using lower bound and upper bound use vectors no need for an unordered map |
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2019-07-30 18:44:26
Are a,b,c,d,e,f distinct? |
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2019-07-04 14:54:42
Easy question..lower bound and upper bound is the key to solve this |
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2019-07-04 07:03:01
nice!!! |
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2019-06-20 08:55:01
Just make sure to check for d==0 case and maintain complexity of O(N^3) at max. |
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2019-05-31 15:19:16
sexy |
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2019-04-21 16:46:05 Jumpy
The above equations can be written as: a * b + c = (f+e) *d , with exception d can't be 0 'zero'. Now, the complexity can be reduced to N^3. |
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2019-04-10 18:45:16
while using unordered map initialize the size as N^3, in order to avoid TLE |
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2019-04-07 22:51:20
Don't forget to use unordered_map! Cost me 1 WA |