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AE00 - Rectangles |
Byteman has a collection of N squares with side 1. How many different rectangles can he form using these squares?
Two rectangles are considered different if none of them can be rotated and moved to obtain the second one. During rectangle construction, Byteman can neither deform the squares nor put any squares upon any other ones.
Input
The first and only line of the standard input contains one integer N (1 <= N <= 10000).
Output
The first and only line of the standard output should contain a single integer equal to the number of different rectangles that Byteman can form using his squares.
Example
For the input data:
6
the correct result is:
8
Task author: Jakub Radoszewski.
Added by: | Race with time |
Date: | 2009-05-03 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | Algorithmic Engagements 2009 |
hide comments
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2019-02-22 15:23:15
Don't forget to initialize your count to 0. AC on 6th attempt. |
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2019-01-05 13:21:38
Ac in one go |
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2018-12-11 20:15:53
AC in one go! O(√n) Last edit: 2018-12-11 20:18:24 |
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2018-10-11 09:17:21 Joeffison [UFCG]
I got the pattern. Hint: Try n until 10 (when you're reaching the 3rd line, you'll see the pattern) My solution takes O(√n) |
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2018-09-30 02:07:24
can we solve in O(1) time |
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2018-09-24 16:25:30
Helpppp!!!! I count for each factor of N Factor i, multiple it from 1 to int(N/i) and get the total answer but it's wrong, can you guys give me some more example? About n = 60? Thanks. Last edit: 2018-09-24 16:27:59 |
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2018-09-19 09:01:15
It is just an easy math... You can solve it using 2 loops. But you need to do a little bit of optimization. Hint:- You can do it in o(sqrt(n)) |
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2018-08-05 09:10:18
Ac in one go! so ez |
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2018-06-23 12:18:09
try to see or figure out some formula,hint:loop will run upto sqrt(n) to calculate sum*******TC (root_n) |
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2018-05-19 18:55:15
Easy Peasy Lemon Squeezy! |