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AE00 - Rectangles |
Byteman has a collection of N squares with side 1. How many different rectangles can he form using these squares?
Two rectangles are considered different if none of them can be rotated and moved to obtain the second one. During rectangle construction, Byteman can neither deform the squares nor put any squares upon any other ones.
Input
The first and only line of the standard input contains one integer N (1 <= N <= 10000).
Output
The first and only line of the standard output should contain a single integer equal to the number of different rectangles that Byteman can form using his squares.
Example
For the input data:
6
the correct result is:
8
Task author: Jakub Radoszewski.
Added by: | Race with time |
Date: | 2009-05-03 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO NODEJS PERL6 VB.NET |
Resource: | Algorithmic Engagements 2009 |
hide comments
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2017-05-27 17:40:05
AC in one go, simply use general mathematics no use of using DP, just basic Ad-hoc |
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2017-05-25 11:49:33
AC IN ONE GO... |
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2017-04-19 08:07:10
AC on one go though took about 30-35 mins to be sure of correctness of my soln!! Little tedious but interesting problem! |
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2017-03-30 20:31:43
AC in one go booya ruchir |
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2017-03-21 09:40:15
AC in one! my 6th! :D |
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2017-03-11 12:34:20
little bit of math... |
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2017-03-08 11:30:46
:| badihie Last edit: 2017-03-08 11:31:02 |
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2017-02-14 08:29:38
AC in 1 GO with 5 lines :"> |
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2017-01-24 17:15:45
Using some elementary summing formulas, you can get it down to a formula that's calculated in O(sqrt(n)) time. |
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2017-01-03 12:57:10
Calculating the number of possible rectangles for each squares takes O( sqrt(n) ) time. To do that for n numbers 1, 2, 3, 4.....n, takes O( n * sqrt(n) ) operations. So that makes it O(n ^ 1.5) complexity. Correct me if I'm wrong. |