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CANTON - Count on Cantor |
One of the famous proofs of modern mathematics is Georg Cantor's demonstration that the set of rational numbers is enumerable. The proof works by using an explicit enumeration of rational numbers as shown in the diagram below.
1/1 1/2 1/3 1/4 1/5 ... 2/1 2/2 2/3 2/4 3/1 3/2 3/3 4/1 4/2 5/1
In the above diagram, the first term is 1/1, the second term is 1/2, the third term is 2/1, the fourth term is 3/1, the fifth term is 2/2, and so on.
Input
The input starts with a line containing a single integer t <= 20, the number of test cases. t test cases follow.
Then, it contains a single number per line.
Output
You are to write a program that will read a list of numbers in the range from 1 to 10^7 and will print for each number the corresponding term in Cantor's enumeration as given below.
Example
Input: 3 3 14 7 Output: TERM 3 IS 2/1 TERM 14 IS 2/4 TERM 7 IS 1/4
Added by: | Thanh-Vy Hua |
Date: | 2005-02-27 |
Time limit: | 5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |
Resource: | ACM South Eastern European Region 2004 |
hide comments
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2015-01-28 19:17:53 Harsh Shah
Learnt new technique, great question. |
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2015-01-18 11:40:51 :.Mohib.:
Easy...got It..... :) |
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2015-01-01 18:55:57 SM_92
Last edit: 2015-01-03 09:35:52 |
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2014-12-24 19:49:53 Saksham
ac in first go just focus diagnally |
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2014-12-11 07:13:32 kartikay singh
AC in 0.0 sec yepieee |
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2014-12-11 07:12:41 kartikay singh
silly mistakes cost me 2 WA but finally AC ......... dont forget to use long long int in c |
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2014-10-26 17:12:39 mohmmad ali
u have to give more time to this,may use concept of triangular numbers |
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2014-09-21 19:12:05 KAI
yeah 1st go :) |
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2014-09-20 13:33:37 Siya
AC in first attempt :) |
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2014-09-10 09:28:16 Nabeel
After a great thinking,,,, GOT AC :) |