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CANTON - Count on Cantor |
One of the famous proofs of modern mathematics is Georg Cantor's demonstration that the set of rational numbers is enumerable. The proof works by using an explicit enumeration of rational numbers as shown in the diagram below.
1/1 1/2 1/3 1/4 1/5 ... 2/1 2/2 2/3 2/4 3/1 3/2 3/3 4/1 4/2 5/1
In the above diagram, the first term is 1/1, the second term is 1/2, the third term is 2/1, the fourth term is 3/1, the fifth term is 2/2, and so on.
Input
The input starts with a line containing a single integer t <= 20, the number of test cases. t test cases follow.
Then, it contains a single number per line.
Output
You are to write a program that will read a list of numbers in the range from 1 to 10^7 and will print for each number the corresponding term in Cantor's enumeration as given below.
Example
Input: 3 3 14 7 Output: TERM 3 IS 2/1 TERM 14 IS 2/4 TERM 7 IS 1/4
Added by: | Thanh-Vy Hua |
Date: | 2005-02-27 |
Time limit: | 5s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |
Resource: | ACM South Eastern European Region 2004 |
hide comments
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2015-08-17 21:42:18 suhas
Awesome... AC at 1st go. :) |
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2015-08-17 15:14:29 Babloo
My 20th. Green in FIRST GO!! |
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2015-08-16 11:37:59 Ravi Chandra
I hate this problem.Spent three hours.And at last AC in one go |
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2015-08-03 19:25:44 Yuvak Patel
Just observe the pattern!! |
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2015-07-25 11:41:39 Dipanshu Mittal
I got WA just becoz "is" is not "IS". |
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2015-07-24 21:14:53
HINT: Consider a triangle with diagonals as rows and then try to find the pattern. |
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2015-07-18 20:34:30 Amit Verma
please explain.. Not getting it .. :( |
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2015-06-28 13:36:42 Anurag Pasi
Easy one :) just find the pattern and apply the simple logic , AC in 1 go :) |
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2015-06-20 09:22:15 Rahul Kumar
dont forget to use long long int ,thanks @ karthikey ,use arrow ,where the pattern is moving ,find the relation. |
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2015-06-19 01:49:06
Easy to solve using math and geometry. It's possible to get an equation to find the X and Y position of the requested term on the grid |