CANTON - Count on Cantor

One of the famous proofs of modern mathematics is Georg Cantor's demonstration that the set of rational numbers is enumerable. The proof works by using an explicit enumeration of rational numbers as shown in the diagram below.

1/1 1/2 1/3 1/4 1/5 ...
2/1 2/2 2/3 2/4
3/1 3/2 3/3
4/1 4/2
5/1

In the above diagram, the first term is 1/1, the second term is 1/2, the third term is 2/1, the fourth term is 3/1, the fifth term is 2/2, and so on.

Input

The input starts with a line containing a single integer t <= 20, the number of test cases. t test cases follow.

Then, it contains a single number per line.

Output

You are to write a program that will read a list of numbers in the range from 1 to 10^7 and will print for each number the corresponding term in Cantor's enumeration as given below.

Example

Input:
3
3
14
7

Output:
TERM 3 IS 2/1
TERM 14 IS 2/4
TERM 7 IS 1/4

Added by:Thanh-Vy Hua
Date:2005-02-27
Time limit:5s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS PERL6 VB.NET
Resource: ACM South Eastern European Region 2004

hide comments
2016-09-12 02:07:26
Please help me...it is mentioned in the question that the 4th term is 3/1.....is it correct...i think it should be 1/3..it would form a pattern then
2016-08-30 22:38:35
plot the graph to get the pattern
2016-08-17 16:53:09
AC in first attemp :) time - 0.00
2016-08-11 21:22:32 sharif ullah
here number of test case is 20 .so pre-calculation may give TLE
2016-07-16 17:48:38 SidXDDD


Last edit: 2016-07-20 16:02:11
2016-07-13 16:52:09 Pikachu


Last edit: 2016-07-13 16:56:04
2016-06-24 18:56:10
AC in first try, 0.06 seconds in Java. Just observe the pattern and the rest is very simple, no algorithm needed!
2016-06-19 13:08:28
A very nice question... Just pick a paper & try to find the pattern
You will enjoy when you will finally get AC :)

AC in 2nd go, just missed that "IS" in caps.
2016-06-17 19:37:26
Easy but nice question.
2016-06-16 16:32:33
Easy ... AC in one go.... 0.00 Time !!
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